Legacy ImageMagick Discussions Archive

Hi Bonzo,

looking at the version string you are absolutely right. I should have noticed that. Just wondering where the (nearly) up-to-date timestamp comes from. Obviously it fooled me...
Version: ImageMagick 6.7.7-10 2017-05-26

Is the timestamp related to the distros build date and not the ...

Hi,

looks to me like this issue came up again, I am using ImageMagick on Linux Mint 17.2:

Version: ImageMagick 6.7.7-10 2017-05-26 Q16 http://www.imagemagick.org
Copyright: Copyright (C) 1999-2012 ImageMagick Studio LLC
Features: OpenMP

strokewidth = 2 works fine and produces a proper rectangle ...

Hi magick,

As usual: thanks for the fast fix - ImageMagick 6.7.2-9 2011-09-23 on Windows XP works as expected.

Best, Andreas

I am using ImageMagick 6.7.2-8 2011-09-23 Q16 on Windows XP.

When rotating images I get torn images (black stripes) for a certain range of angles. I also had a couple of crashes but they seem not to be reproducible.

convert rose: -rotate 45 rotate45.jpg -> good
convert rose: -rotate 46 rotate46 ...

Hi magick,

This makes everybod happy: XNView, djv_view happy and me. Thanks a lot!
Andreas

Hi magick,

thanks for your reply!

Your posting suggests that perhaps one of the programs you listed may not read and / or write DPX images properly, however you did not specifically identify that the problem is with ImageMagick.
XNView never let me down in the past with DPX files and I find it a ...

Hi all,

not sure this is a bug or because of an error I do...

I try to annotate text to 10 bit DPX images but getting very different results when displaying them in the programs listed below (all run under Windows XP).

I am using ImageMagick 6.7.2-8 2011-09-23 Q16 under Windows XP to create the ...

Hi Fred,

I got me the official ASC specs in the meantime and Wikipeda is right:
The input value, slope, ranges from 0.0 (constant output at Offset) to less than infinity
...
out = in * slope 0 ≤ slope < ∞
Since I need to stay conform with the ASC standards: no more need to fiddle around.

Thanks ...

Hi Fred,

Standard CDL does not seem to support slope values less than 0 (though I suppose it could be made so, i.e. -1 to 1). See http://en.wikipedia.org/wiki/ASC_CDL "s is slope (any number 0 or greater, nominal value is 1.0)"
you are right, will try to find out if Wikipedia is correct here ...

Hi all,

I am trying to use ASC CDL to
a) invert an image (negative)
b) removing all color (b&w negative)
c) I have to use CDL although I know there are other ways ;-)

this is my main code:
convert -cdl cdl_Invert.txt rose: rose_invert.jpg
and here is cdl_Invert.txt:

<?xml version="1.0 ...

Anthony,
I thought you were taking about reducing images from 10bit to 8bit not reducing number of colors.
no, that´s a misunderstanding. The question is: is the image content of the 10bit DPX really 10bit or only 8bit?

In the meantime I found something which might probably work for me, will have ...

Anthony,
I would like to see some image processing operators for generating histograms and other plots based on image data of any size, but that is on a long list of 'wishes, wants and desires; :-(
But at least you are not alone :)

But what you probably want is NOT the image, but the text ...

Thanks again Anthony will give it a try.

On a slightly different topic: when I "histogram" a 10bit (DPX) image with
convert orig10bit.dpx -define histogram:unique-colors=false histogram:orig10bit.dpx_h.gif the resulting GIF is 256x100 pixels. I would have expected a width of 1024 having one pixel ...

Dear Anthony,

thanks for the fast reply. I guess I somehow understand what you mean but can you give me a clue if this can be done with ImageMagick?

Thanks, Andreas

Hi all,

my problem is the following: I have to check within 10bit DPX files if the image content had gone through an 8bit bottleneck before.

bitdepth ( identify -format %z filename ) will tell me that my DPX file is a 10bit container and identify -format %k filename would give me the number of ...