The SR result about the alphabets are very good
I could tell what are the alphabets of the last line
even with my eyes without relying on OCR, pretty amazing.
I remember our professor said that fractal base algorithm is patent?
Do that mean we have to pay money if we want to implement
this ...
Search found 3 matches
- 2013-01-25T07:54:31-07:00
- Forum: Digital Image Processing
- Topic: future of image enlargement?
- Replies: 61
- Views: 206918
- 2013-01-20T01:17:20-07:00
- Forum: Bugs
- Topic: Sigmoidal equation(bug?) of image magick
- Replies: 7
- Views: 10203
Re: Sigmoidal equation(bug?) of image magick
Thanks, the result are much more closer to the equation --(1/(1+exp(10*(.5-u)))-0.0066928509)*1.0092503
Although the last one has some different(precision problem?But double also give the same answer).
exponential version
inline float sigmoidal(float contrast, float threshold, float signal ...
Although the last one has some different(precision problem?But double also give the same answer).
exponential version
inline float sigmoidal(float contrast, float threshold, float signal ...
- 2013-01-19T06:49:16-07:00
- Forum: Bugs
- Topic: Sigmoidal equation(bug?) of image magick
- Replies: 7
- Views: 10203
Sigmoidal equation(bug?) of image magick
According to this page
http://www.imagemagick.org/Usage/color_mods/#sigmoidal
The equation of the sigmoidal should be
(1/(1+exp(β*(α-u))) - 1/(1+exp(β))) / (1/(1+exp(β*(α-1)))/(1+exp(β)))
In general, the Beta is 10 and the alpha is 0.5, IM give us a simple
command "-fx" with default Beta and ...
http://www.imagemagick.org/Usage/color_mods/#sigmoidal
The equation of the sigmoidal should be
(1/(1+exp(β*(α-u))) - 1/(1+exp(β))) / (1/(1+exp(β*(α-1)))/(1+exp(β)))
In general, the Beta is 10 and the alpha is 0.5, IM give us a simple
command "-fx" with default Beta and ...